KJH Report Extra 2021 (Korrigierte Fassung)

2019 1.3.5 Anzahl der 14- bis unter 16-Jährigen 1,7 Mio. 2006 1,5 Mio. 2016 1,5 Mio. 2018 1,5 Mio. 2019 1.3.6 Anzahl der 16- bis unter 18-Jährigen 1,9 Mio. 2006 1,6 Mio. 2016 1,6 Mio. 2018 1,5 Mio. 2019 [...] 21-Jährigen 2,9 Mio. 2006 2,6 Mio. 2016 2,6 Mio. 2018 2,5 Mio. 2019 1.3.8 Anzahl der 21- bis unter 27-Jährigen 5,9 Mio. 2006 5,8 Mio. 2016 5,7 Mio. 2018 5,7 Mio. 2019 Migra onshintergrund 1.4 Anteil unter [...] Personal 10.5 Berufl iches Personal mit dem Arbeitsschwerpunkt Amtsvormundscha en, Amtspfl egscha en und Beistandscha en 10.5.1 Anzahl des Personals 3.525 2006 5.473 2016 5.489 2018 / 10.5.2 Anzahl der …

d(λ)|λ=1/5 = (1− d)d5d − (2− 2d)52d−1 = (1− d)5d(d− 2 · 5d−1) ≤ (1− d)5d(d− 2( 2− ln(5) 2 √ 5 + d ln(5)√ 5 ) , wegen (A.1), = (1− d)5d( √ 5(ln(5)− 2) 5 + 5− 2 √ 5ln(5) 5 d) ≤ (1− d)5d( √ 5(13/7− 2) 5 + 5− 2 [...] dass 5c−3/2 und 5−c−3/2 konvex sind. Anwendung von (5.42) liefert 5c−3/2 ≥ 5−3/2 + ln(5) 5 √ 5 c 123 und 5−c−3/2 ≥ 5−3/2 − ln(5) 5 √ 5 c. Daraufhin gilt, dass t2( 1 5 , c) ≥ (2c+ 1)(5−3/2 + ln(5) 5 √ 5 [...] 2 √ 5 · 3/2 5 d) , wegen (A.3), = (1− d)5d(− √ 5 35 + 5− 3 √ 5 5 d) ≤ (1− d)5d(− √ 5 35 − 1 5 d) , wegen √ 5 > 2, < 0. (A.5) Aus (A.5) ist ersichtlich, dass s4,d(λ) für d ∈ [1/2, 1) in λ = 1/5 streng monoton …

Microsoft Word - Scheiner AP Wohn-LS-Mobilität Methodik.doc

Ehrenfeld peripher* 0,20 5,3 61,0 135,9 75,4 58,4 69,0 92,5 zentral* 0,16 7,0 72,5 158,7 87,8 73,9 81,2 111,0 Nippes peripher* 0,21 7,4 62,3 84,5 58,6 34,8 86,0 118,5 zentral* 0,11 7,5 77,4 106,1 76,1 44,6 [...] peripher* 0,37 1,5 12,9 8,9 7,7 5,1 65,5 6,1 zentral* 0,21 1,9 14,2 11,1 9,2 8,6 66,7 7,5 Longerich peripher* 0,49 1,6 9,2 17,2 13,7 12,4 7,9 16,2 zentral* 0,17 2,0 9,3 15,6 11,4 13,4 7,5 18,1 Esch peripher* [...] 0 0 0 Maximum 1,05 7 17 47 30 30 52 22 Heiligenhaus Mittelwert 2,29 0 5 3 2 5 18 3 Minimum 1,27 0 0 0 0 0 0 0 Maximum 3,50 0 9 5 5 9 39 6 Insgesamt Mittelwert 0,66 3 21 36 23 18 44 36 Minimum 0,00 0 0 …

0000673) (0.0000660) (0.0000677) (0.0000683) (0.0000671) (0.0000663) ROA t-1 5.679*** 5.842*** 5.522*** 5.634*** 5.674*** 5.622*** (0.562) (0.578) (0.563) (0.560) (0.562) (0.574) Market value t-1 0.000316 [...] density estimate Normal density kernel = epanechnikov, bandwidth = 0 0 .5 1 1 .5 D e n s it y -3 -2 -1 0 1 2 Residuals (log) 0 .5 1 1 .5 D e n s it y -3 -2 -1 0 1 2 Residuals (log) Kernel density estimate [...] n 0 .2 .4 .6 D e n s it y -10 -5 0 5 EBIT-margin (log) 63 Data and empirical methodology without adding variables of a Pearson correlation coefficient of higher than 0.5 (as explained further above). As …

Institut für Sport und Sportwissenschaft

Persons with MS had mild to moderate disease severity (Expanded Disability Status Scale [EDSS] score ≤6.5). Following the investigation of individual metabolites, we explored KP metabolite patterns using e [...] aerobic training is not the most efficacious exercise type to reduce fatigue in pwMS. Publications 2-5 then developed a new group-based multimodal agility-based exercise training (MAT) framework centered [...] weight = 60.63 ± 9.58, height = 166.55 ± 6.49, BMI = 21.81 ± 2.84) participated in this study. Following a 5-min warm-up, each participant underwent a standardized screening battery including the FMS, YBT, and …

−0.5 0.0 Hours Worked 0 5 10 15 −1.5 −1.0 −0.5 0.0 Credit 0 5 10 15 0.0 0.5 1.0 1.5 Investment 0 5 10 15 0.0 0.2 0.4 Interest Rate 0 5 10 15 −0.008 −0.006 −0.004 −0.002 0.000 0.002 Credit Price 0 5 10 [...] Wage 0 5 10 15 0.0 0.5 1.0 Hours Worked 0 5 10 15 0.0 0.5 1.0 1.5 2.0 Credit 0 5 10 15 0.0 1.0 2.0 3.0 Investment 0 5 10 15 −0.6 −0.4 −0.2 0.0 Interest Rate 0 5 10 15 0.000 0.005 0.010 Credit Price 0 5 10 [...] 0.4 Real Wage 0 5 10 15 −1.0 −0.5 0.0 Hours Worked 0 5 10 15 −0.8 −0.6 −0.4 −0.2 0.0 Credit 0 5 10 15 −0.5 0.0 0.5 1.0 1.5 Investment 0 5 10 15 −0.8 −0.6 −0.4 −0.2 0.0 Interest Rate 0 5 10 15 −0.20 −0.15 …

(See also 1.5.5 below ) Definition 1.5.5. Let R, x0 as above. Inv(R) := {γ ∈ Aff0(R), γ ↗ : ∃ xγ ≥ x0 such that R(γ(x)) = R(x), x ≥ xγ}. Inv(R) is called the invariance group of R. Proposition 1.5.6. For d [...] c(t) · Λ( ⇀ x) , ⇀ x> ⇀ 0 (2.5.1) Assume in 2.5.1 that (γ(t)( ⇀ x))i t→∞−→ ∞ , 1 ≤ i ≤ d, ⇀ x> ⇀ 0 (2.5.2) Furthermore 0 ≤ Λ ≤ 1 and Λ( ⇀ x) → 0 if xi →∞, 1 ≤ i ≤ d. (2.5.3) 72 The solution in the continuous [...] According to 2.5.2, and 2.5.3 we have c(t) t→∞−→ 0, for t→∞ hence we write β = −α for some α > 0. Therefore, the extension of Λ is given by Λ(γ(t)( ⇀ x)) = t−α · Λ( ⇀ x) , ⇀ x∈ Aγ, t > 0. (2.5.5) Note that …