buffer 1 4 4 buffer 2 1 1 buffer 3 1 1 buffer 4 2 4 buffer 5 2 4 buffer 6 3 4 buffer 7 2 4 buffer 8 1 4 buffer 9 1 3 buffer 10 3 2 buffer 11 14 10 buffer 12 3 8 buffer 13 1 0 buffer 14 3 2 buffer 15 4 7 buffer [...] 0. 82 -1 89 .8 8. 52 4. 77 5. 60 17 9 12 1 59 1 4 0 1 G ly ci n e -1 0. 21 1. 08 -8 9. 0 4. 18 4. 56 5. 64 11 2 79 33 0 0 0 0 H is ti d in e -9 .1 6 0. 79 -3 7. 4 10 .4 6 4. 19 4. 98 19 6 98 98 1 1 1 0 [...] .7 4. 37 4. 11 3. 51 -2 .4 1 S er in e 10 5. 1 44 19 15 6 36 23 13 18 .3 4. 18 3. 87 3. 31 -2 .7 4 T h re on in e 11 9. 1 58 25 27 11 46 39 30 28 .5 3. 97 3. 57 3. 08 -2 .4 3 T ry p to p h an 20 4. 2 86 …

in equations 1.4.3, 1.4.5, 1.4.8, and 1.4.9 are solutions of the functional equation in the continuous case. And in the discrete case, as easily seen in 1.4.12, 1.4.13, 1.4.14, and 1.4.16 we obtain solutions [...] In example 0.4.4 similarly we obtain that the standard Pareto distri- bution does not possess the L.M.P. But this distribution satisfies an equation similar to (1.1.4). Examples 0.4.4 - 0.4.20 can be treated [...] 0, d ≥ 0) (1.4.4) Put z = d · (uQ − 1) ≥ 0 hence u = (1 + z d ) 1 Q . And the solution of the func- tional equation (using 1.4.4) obtains the form Λ(z) = c · (1 + z d ) −β Q , z ≥ 0. (1.4.5) With C = c …

The distribution of paid work among couples

1  64,4  67,9  72,7  ‐9,6  ‐6,2  ‐1,4  BG  75,1  41,6  59,4  72,0  ‐33,6  ‐15,7  ‐3,2  CY  76,5  69,4  73,1  74,8  ‐7,0  ‐3,3  ‐1,6  CZ  69,2  18,9  53,4  61,5  ‐50,4  ‐15,8  ‐7,7  DK  79,4  71,4  77,8  [...] 7:57  7:10  8:35  men  4:06  4:07  4:24  4:56  5:10  employed total  3:58  5:02  5:35  5:56  6:19  employed women  6:00  5:55  7:08  7:01  7:44  employed men  4:46  4:05  4:18  4:50  5:09   Note: Data  [...] 37,6  35,8  12,5  12,2  10,4  NL  78,2  72,9  73,3  75,7  ‐5,4  ‐4,9  ‐2,5  PL  70,2  49,3  56,4  67,9  ‐20,9  ‐13,8  ‐2,3  PT  76,5  67,4  71,6  76,4  ‐9,1  ‐4,9  ‐0,1  13 Results of research review – …

= (λ8d−4 − λ6d−2 + λ6d−4 − 4λ4d−2 + λ2d−2 + 2λ4d − λ2d + 1)d2 + (−2λ6d−2 + 4λ4d−2 − 2λ2d−2 − 2λ4d + 4λ2d − 2)d + λ6d−2 − 2λ4d−2 + λ2d−2 + λ4d − 2λ2d + 1, n1(λ, d) = λ8d−2 − 2λ6d−2 + λ4d+2 + λ4d−2 − 2λ2d+2 [...] λ)(λ+ 1)(3λ− 4λ3/4 − 12λ1/4 + 13) )1/2. Die erste Ableitung von 8(1−λ1/2)2(λ+λ1/2 +1)/[(1−λ)(λ+1)(3λ−4λ3/4−12λ1/4 +13)] lautet dann m2(λ) ((1− λ)(λ+ 1)(3λ− 4λ3/4 − 12λ1/4 + 13))2 mit m2(λ) = 4(λ1/4 − 1)6(λ1/4 [...] = 8(λ1/4 − 1)6(λ1/4 + 1)2(28λ31/4 + 84λ15/2 + 189λ29/4 + 344λ7 + 564λ27/4 + 852λ13/2 + 1218λ25/4 + 1640λ6 + 2096λ23/4 + 2596λ11/2 + 3086λ21/4 + 3608λ5 + 4076λ19/4 + 4564λ9/2 + 4877λ17/4 + 5128λ4 + 5132λ15/4 …

Data 1992 Data 2007 Q1 2.7 −0.4 −0.1 0.0 −0.4 −0.2 Q2 3.9 3.2 4.2 1.8 1.7 1.1 Q3 10.7 12.5 11.7 6.1 5.7 4.5 Q4 19.8 23.3 20.8 15.7 13.4 11.2 Q5 62.9 61.4 63.5 76.4 79.6 83.4 Gini 0.61 0.63 0.64 0.75 0.78 [...] no-Ponzi condition (4.25), 3. factor prices (4.8) and (4.9), capital accumulation (4.16), profits definition (4.7) and production technology (4.5), 4. the aggregation identities (4.30) and (4.31), and 99 INCOME [...] conditions (4.18)-(4.20), with binding budget constraint (4.15) and transversality conditions (4.21) and (4.22), 2. the workers’ first order conditions (4.26)-(4.28), with binding budget constraint (4.24) and …

30 0.1 10 280.4 595.7 4.563 4.530 0.033 0.05 10 580.2 1314.5 4.664 4.589 0.075 0.03 10 1017.1 2420.0 4.697 4.565 0.132 0.02 10 1685.4 4235.4 4.804 4.577 0.227 0.01 10 4237.0 11599.1 5.179 4.564 0.615 40 [...] 0 0 .1 1 0 4 .0 1 7 .4 0 .2 0 1 0 1.1 6767.8 10.58 0 .5 1 0 6 .8 4 5 .6 0 .4 7 1 0 44.5 7297.1 14.60 1 1 0 7 .2 8 5 .0 0 .8 7 1 0 796.9 11963.0 38.14 2 0 0 7 9 6 0 0 0 .1 1 0 4 .0 2 4 .4 1 .4 2 1 0 2.1 [...] 1 0 2 4 .8 1 7 6 .3 7 .9 7 1 0 123.7 28982.2 153.07 1 1 0 1 6 4 .2 1 1 6 5 .8 4 5 .3 0 9 6 067.8 116059.3 891.38 3 0 0 1 7 9 4 0 0 0 .1 1 0 6 .4 2 2 .1 5 .7 5 1 0 2.4 62384.8 399.66 0 .5 1 0 1 4 .6 1 0 …

1 = g4 ergibt sich ein von Null verschiedener differentieller Rest mit pw(g4) = 3. 7) Also setzen wir G = {g1, g2, g3, g4}, s̃ = 4 und zugleich B = {(1, 1), (2, 2), (1, 4), (2, 4), (3, 4), (4, 4)} bzw [...] B3 = {((1, 0), (4, 0))}. 5) Für das kritische Paar ((1, 0), (4, 0)) ergibt sich für das zugehörige S-Polynom direkt S((1, 0), (4, 0)) = y (1) 1 g1 + y2g4 = 0. Also setzen wir w = 4. 3) Wir streichen [...] streichen das Paar (2, 4) aus B. 4) Es ist B4 = {((1, 2), (1, 1)), ((2, 1), (2, 0)), ((1, 0), (4, 1)), ((3, 0), (4, 1))}. 6) Das kritische Paar ((1, 2), (1, 1)) erfüllt keines der Kriterien C1)–C3) und für das …

------------------------------- 94 4.4 STUDY SITE AND JUSTIFICATIONS ------------------------------------------------------------------------------------------- 95 4.5 UNIT SELECTION FROM THE GOVERNORATES [...] ---------------------------- 112 4.7.3 QUALITATIVE INTERVIEWEE --------------------------------------------------------------------------------------------- 113 4.7.4 CODING OF THE QUALITATIVE DATA -- [...] ------------------------------ 133 5.4.3 INCOME AND MIGRATION IN MERGASUR ------------------------------------------------------------------------------ 134 5.4.4 VILLAGERΩS SATISFACTION AND RURAL POLICIES …

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